Oxidation Number
Electrochemistry

Oxidation Number


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Species

Oxidation No. (ON)

Example:

Species (ON)

Free Elements

= Zero

Mg (0), Cl2 (0)­, S8 (0)

Monoatomic Ions

= Charge on Ion

Ca2+ (+2), O2 (-2)

Polyatomic Ions

Sum of ON = Charge on Ion *

SO42

Let the ON of S be x.

x + 4(-2) = -2; x = +6

Neutral Compounds/ Molecules

Sum of ON = Zero *

NCl3

Let the ON of N be x.

x + 3(-1) = 0; x = +3

* requires memorising of the common ON of elements:

 

Element

Oxidation No. (ON)

Hydrogen (H)

+1

Oxygen (O)

-2

Halogens (X)

-1

 

Practice:


Determine the oxidation numbers of the underlined atoms in the following species:

 

(a) P4

(b) Cr3+

(c) VO2+

(d) MnO2

 

Universal method for determining ON:

  1. Break all bonds in species
  2. Assign shared e- to more electro-ve atom
  3. ON = resultant charge on atom

Example: HCN

Practice:


Determine the oxidation numbers of the elements in carbon disulfide CS2.





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