Electrochemistry
Redox Titrations (Unknown Oxidation No.)
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- Determine the reacting ratio between the reactants.
- Construct the following table:
| Rxt A | Rxt B |
Reacting ratio | P | R |
n of e– transferred per mol of reactant (= change in ON) | Q | S |
Total n of e– transferred (P x Q or R x S) | P x Q = R x S |
- Since total n of e- transferred must be the same for both reactants, make use of the relation (PxQ = RxS) to obtain the number of electrons transferred by the reactant with the unknown ON (Q or S).
- Consider whether the reactant had undergone oxidation or reduction; Add or subtract Q or S accordingly to get initial/ final unknown oxidation state.
Example: 100 cm3 of 0.20 mol dm–3 acidified Fe2+ is oxidized by 50 cm3 of a solution containing 0.20 mol dm–3 of MO3–. Determine the final oxidation state of M. | Fe2+ | MO3– | Reacting ratio | 2 | 1 | n of e– transferred per mol of reactant | 1 Fe2+ → Fe3+ + 1e– | ? | Total n of e– transferred | 2 | - Using the relation P x Q = R x S, n of e– transferred per mol of MO3– = 2
- Fe2+ is oxidised so MO3– must be reduced.
- Initial ON of M in MO3– is +5 → Final ON = +5 – 2 = +3
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Practice:
0.5 g of Zn was reacted with an acidified solution of 25.50 cm3 of 0.200 mol dm–3 MO2+. What is the final oxidation number of metal M?
[Ans: –1]
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Electrochemistry